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Example 6.3 · Strip footing

Example 6.3 of Das & Sivakugan (2017), Principles of Foundation Engineering, solved in Rischio: allowable load per metre, FS 3, beside the source's answers.

Source
Das, B. M., & Sivakugan, N. (2017). Principles of Foundation Engineering, SI edition, 9th ed. Cengage Learning. Example 6.3.
ID
das-pfe9-6-3
Open in the studioA copy, in your account
47.0 kPa47.0 kPa
The model as the editor draws it, with what governs its result.

Source vs Rischio

SourceRischioDifference
Allowable load per metre, FS 3621 kN/m622 kN/m+0.1 %

Every check

What the engine checks in this model, against Rischio's default limits.

Bearing capacityPassesFS=19.87\mathrm{FS} = 19.87≥3.0\ge 3.0
Eccentricity along the widthPasseseB=0.00 me_B = 0.00\,\mathrm{m}≤0.333 m\le 0.333\,\mathrm{m}

The model

The example's data, element by element, as the model holds it.

FootingFooting · Strip

Width BB
2 m
Embedment depth DD
1.5 m

LoadLoad · per metre run

Vertical load VV
93.9 kN
Horizontal load HH
0 kN
Moment along the width MBM_B
0 kN·m

SoilStratum

Unit weight γ\gamma
19 kN/m³
Cohesion c′c'
10 kPa
Friction angle φ′\varphi'
26 °

How it's calculated

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