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Toe resistance

How Rischio calculates a pile's toe resistance after Meyerhof, in sand and in clay, and why in sand it stops growing past the first few metres.

Along with the shaft resistance, the toe resistance QpQ_p makes up a pile’s ultimate capacity, Qu=Qs+QpQ_u = Q_s + Q_p. Units, symbols and assumptions are set out in Method and assumptions.

Qp=qpApQ_p = q_p A_p, with qpq_p from the stratum the toe rests on; a toe exactly on a boundary rests on the stratum below. Both cases follow Meyerhof.

In sand

qp=min⁡(q′Nq∗,  0.5 paNq∗tan⁡ϕ′)q_p = \min(q' N_q^{\ast}, \; 0.5 \, p_a N_q^{\ast} \tan\phi'), where q′=σv′(L)q' = \sigma'_v(L) is the effective stress at the toe, not limited by the critical depth zcz_c.

Nq∗N_q^{\ast} is interpolated linearly in ϕ′\phi' from Meyerhof’s values, as Das & Sivakugan (2017) tabulate them from 20° to 45°. Outside that range the end value holds: 12.4 below 20°, 930 above 45°.

ϕ′\phi'Nq∗N_q^{\ast}ϕ′\phi'Nq∗N_q^{\ast}
20°12.433°96.0
21°13.834°115.0
22°15.535°143.0
23°17.936°168.0
24°21.437°194.0
25°26.038°231.0
26°29.539°276.0
27°34.040°346.0
28°39.741°420.0
29°46.542°525.0
30°56.743°650.0
31°68.244°780.0
32°81.045°930.0

As Nq∗N_q^{\ast} multiplies both terms, the limit governs once q′>0.5 patan⁡ϕ′q' > 0.5 \, p_a \tan\phi', between 29 and 42 kPa for ϕ′\phi' from 30° to 40°. Past the first few metres, qpq_p no longer grows with depth.

In clay

qp=9 cuq_p = 9 \, c_u. In a pile group, the block’s toe takes Skempton’s factor in place of the 9.

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