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Every step of the calculation

Each equation of the open channel calculation, with its terms: normal flow, the flow regime and the capacity of the section.

The same steps, in the same order, as the calculation report.

1Normal flow

  1. Water surface elevation

    Q(yn)=Σj1njAjRj2/3S1/2=Q(normal depth, the section divided where n changes)Q(y_n) = \Sigma_j \frac{1}{n_j} A_j R_j^{2/3} S^{1/2} = Q \quad \text{(normal depth, the section divided where } n \text{ changes)}

    where QQ discharge (m³/s)

  2. Normal depth

    yn=WSE−zbedy_n = WSE - z_{bed}
  3. Flow area

    A=∫(WSE−z) dxA = \int (WSE - z) \, dx
  4. Wetted perimeter

    P=ΣPiP = \Sigma P_i
  5. Hydraulic radius

    R=A/PR = A / P

    where AA flow area (m²); PP wetted perimeter (m)

  6. Mean velocity

    V=Q/AV = Q / A

    where QQ discharge (m³/s); AA flow area (m²)

2Flow regime

  1. Top width

    TT
  2. Froude number

    Fr=VgA/TFr = \frac{V}{\sqrt{g A / T}}

    where VV mean velocity (m/s); AA flow area (m²); TT top width (m)

  3. Critical depth

    Q2TcgAc3=1\frac{Q^2 T_c}{g A_c^3} = 1

    where QQ discharge (m³/s)

  4. Specific energy

    E=y+V22gE = y + \frac{V^2}{2g}

    where yy normal depth (m); VV mean velocity (m/s)

3Capacity of the section

  1. Bank-full capacity

    Qbank=Σj1njAjRj2/3S1/2(y=ybank)Q_{bank} = \Sigma_j \frac{1}{n_j} A_j R_j^{2/3} S^{1/2} \quad (y = y_{bank})

    where ybanky_{bank} depth to the lower bank (m); SS longitudinal slope (m/m)

  2. Bank-full capacity

    Q≤QbankQ \le Q_{bank}

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