Rischio
Start free

DocsVerified examples

Example 6.7 · Eccentric strip footing

Example 6.7 of Das & Sivakugan (2017), Principles of Foundation Engineering, solved in Rischio: ultimate load per metre, beside the source's answers.

Source
Das, B. M., & Sivakugan, N. (2017). Principles of Foundation Engineering, SI edition, 9th ed. Cengage Learning. Example 6.7.
ID
das-pfe9-6-7
Open in the studioA copy, in your account
20.0 kPa80.0 kPa
The model as the editor draws it, with what governs its result.

Source vs Rischio

SourceRischioDifference
Ultimate load per metre5 260 kN/m5 261 kN/m0.0 %

Every check

What the engine checks in this model, against Rischio's default limits.

Bearing capacityPassesFS=41.10\mathrm{FS} = 41.10≥3.0\ge 3.0
Eccentricity along the widthPasseseB=0.20 me_B = 0.20\,\mathrm{m}≤0.333 m\le 0.333\,\mathrm{m}

The model

The example's data, element by element, as the model holds it.

FootingFooting · Strip

Width BB
2 m
Embedment depth DD
1.5 m

LoadLoad · per metre run

Vertical load VV
100 kN
Horizontal load HH
0 kN
Moment along the width MBM_B
20 kN·m

SandStratum

Unit weight γ\gamma
16.5 kN/m³
Cohesion c′c'
0 kPa
Friction angle φ′\varphi'
40 °

How it's calculated

Type to search: a method, a warning, a field…

↑↓ to move · ↵ to open · esc to close